Optimal. Leaf size=122 \[ \frac {2 i a^2 (c+d x) \cosh (e+f x)}{f}-\frac {a^2 (c+d x) \sinh (e+f x) \cosh (e+f x)}{2 f}+\frac {a^2 (c+d x)^2}{2 d}+\frac {1}{2} a^2 c x+\frac {a^2 d \sinh ^2(e+f x)}{4 f^2}-\frac {2 i a^2 d \sinh (e+f x)}{f^2}+\frac {1}{4} a^2 d x^2 \]
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Rubi [A] time = 0.11, antiderivative size = 122, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 4, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.190, Rules used = {3317, 3296, 2637, 3310} \[ \frac {2 i a^2 (c+d x) \cosh (e+f x)}{f}-\frac {a^2 (c+d x) \sinh (e+f x) \cosh (e+f x)}{2 f}+\frac {a^2 (c+d x)^2}{2 d}+\frac {1}{2} a^2 c x+\frac {a^2 d \sinh ^2(e+f x)}{4 f^2}-\frac {2 i a^2 d \sinh (e+f x)}{f^2}+\frac {1}{4} a^2 d x^2 \]
Antiderivative was successfully verified.
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Rule 2637
Rule 3296
Rule 3310
Rule 3317
Rubi steps
\begin {align*} \int (c+d x) (a+i a \sinh (e+f x))^2 \, dx &=\int \left (a^2 (c+d x)+2 i a^2 (c+d x) \sinh (e+f x)-a^2 (c+d x) \sinh ^2(e+f x)\right ) \, dx\\ &=\frac {a^2 (c+d x)^2}{2 d}+\left (2 i a^2\right ) \int (c+d x) \sinh (e+f x) \, dx-a^2 \int (c+d x) \sinh ^2(e+f x) \, dx\\ &=\frac {a^2 (c+d x)^2}{2 d}+\frac {2 i a^2 (c+d x) \cosh (e+f x)}{f}-\frac {a^2 (c+d x) \cosh (e+f x) \sinh (e+f x)}{2 f}+\frac {a^2 d \sinh ^2(e+f x)}{4 f^2}+\frac {1}{2} a^2 \int (c+d x) \, dx-\frac {\left (2 i a^2 d\right ) \int \cosh (e+f x) \, dx}{f}\\ &=\frac {1}{2} a^2 c x+\frac {1}{4} a^2 d x^2+\frac {a^2 (c+d x)^2}{2 d}+\frac {2 i a^2 (c+d x) \cosh (e+f x)}{f}-\frac {2 i a^2 d \sinh (e+f x)}{f^2}-\frac {a^2 (c+d x) \cosh (e+f x) \sinh (e+f x)}{2 f}+\frac {a^2 d \sinh ^2(e+f x)}{4 f^2}\\ \end {align*}
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Mathematica [A] time = 1.18, size = 86, normalized size = 0.70 \[ \frac {a^2 (-2 (3 (e+f x) (-2 c f+d e-d f x)+f (c+d x) \sinh (2 (e+f x))+8 i d \sinh (e+f x))+16 i f (c+d x) \cosh (e+f x)+d \cosh (2 (e+f x)))}{8 f^2} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.50, size = 162, normalized size = 1.33 \[ \frac {{\left (2 \, a^{2} d f x + 2 \, a^{2} c f + a^{2} d - {\left (2 \, a^{2} d f x + 2 \, a^{2} c f - a^{2} d\right )} e^{\left (4 \, f x + 4 \, e\right )} + {\left (16 i \, a^{2} d f x + 16 i \, a^{2} c f - 16 i \, a^{2} d\right )} e^{\left (3 \, f x + 3 \, e\right )} + 12 \, {\left (a^{2} d f^{2} x^{2} + 2 \, a^{2} c f^{2} x\right )} e^{\left (2 \, f x + 2 \, e\right )} + {\left (16 i \, a^{2} d f x + 16 i \, a^{2} c f + 16 i \, a^{2} d\right )} e^{\left (f x + e\right )}\right )} e^{\left (-2 \, f x - 2 \, e\right )}}{16 \, f^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.22, size = 159, normalized size = 1.30 \[ \frac {3}{4} \, a^{2} d x^{2} + \frac {3}{2} \, a^{2} c x - \frac {{\left (2 \, a^{2} d f x + 2 \, a^{2} c f - a^{2} d\right )} e^{\left (2 \, f x + 2 \, e\right )}}{16 \, f^{2}} + \frac {{\left (i \, a^{2} d f x + i \, a^{2} c f - i \, a^{2} d\right )} e^{\left (f x + e\right )}}{f^{2}} + \frac {{\left (i \, a^{2} d f x + i \, a^{2} c f + i \, a^{2} d\right )} e^{\left (-f x - e\right )}}{f^{2}} + \frac {{\left (2 \, a^{2} d f x + 2 \, a^{2} c f + a^{2} d\right )} e^{\left (-2 \, f x - 2 \, e\right )}}{16 \, f^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.03, size = 215, normalized size = 1.76 \[ \frac {\frac {d \,a^{2} \left (f x +e \right )^{2}}{2 f}+\frac {2 i d \,a^{2} \left (\left (f x +e \right ) \cosh \left (f x +e \right )-\sinh \left (f x +e \right )\right )}{f}-\frac {d \,a^{2} \left (\frac {\left (f x +e \right ) \cosh \left (f x +e \right ) \sinh \left (f x +e \right )}{2}-\frac {\left (f x +e \right )^{2}}{4}-\frac {\left (\cosh ^{2}\left (f x +e \right )\right )}{4}\right )}{f}-\frac {d e \,a^{2} \left (f x +e \right )}{f}-\frac {2 i d e \,a^{2} \cosh \left (f x +e \right )}{f}+\frac {d e \,a^{2} \left (\frac {\cosh \left (f x +e \right ) \sinh \left (f x +e \right )}{2}-\frac {f x}{2}-\frac {e}{2}\right )}{f}+c \,a^{2} \left (f x +e \right )+2 i c \,a^{2} \cosh \left (f x +e \right )-c \,a^{2} \left (\frac {\cosh \left (f x +e \right ) \sinh \left (f x +e \right )}{2}-\frac {f x}{2}-\frac {e}{2}\right )}{f} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.39, size = 167, normalized size = 1.37 \[ \frac {1}{2} \, a^{2} d x^{2} + \frac {1}{16} \, {\left (4 \, x^{2} - \frac {{\left (2 \, f x e^{\left (2 \, e\right )} - e^{\left (2 \, e\right )}\right )} e^{\left (2 \, f x\right )}}{f^{2}} + \frac {{\left (2 \, f x + 1\right )} e^{\left (-2 \, f x - 2 \, e\right )}}{f^{2}}\right )} a^{2} d + \frac {1}{8} \, a^{2} c {\left (4 \, x - \frac {e^{\left (2 \, f x + 2 \, e\right )}}{f} + \frac {e^{\left (-2 \, f x - 2 \, e\right )}}{f}\right )} + a^{2} c x + i \, a^{2} d {\left (\frac {{\left (f x e^{e} - e^{e}\right )} e^{\left (f x\right )}}{f^{2}} + \frac {{\left (f x + 1\right )} e^{\left (-f x - e\right )}}{f^{2}}\right )} + \frac {2 i \, a^{2} c \cosh \left (f x + e\right )}{f} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.35, size = 104, normalized size = 0.85 \[ \frac {a^2\,\left (6\,d\,x^2+12\,c\,x\right )}{8}-\frac {\frac {a^2\,\left (-d\,\mathrm {cosh}\left (2\,e+2\,f\,x\right )+d\,\mathrm {sinh}\left (e+f\,x\right )\,16{}\mathrm {i}\right )}{8}-\frac {a^2\,f\,\left (c\,\mathrm {cosh}\left (e+f\,x\right )\,16{}\mathrm {i}-2\,c\,\mathrm {sinh}\left (2\,e+2\,f\,x\right )-2\,d\,x\,\mathrm {sinh}\left (2\,e+2\,f\,x\right )+d\,x\,\mathrm {cosh}\left (e+f\,x\right )\,16{}\mathrm {i}\right )}{8}}{f^2} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 0.68, size = 359, normalized size = 2.94 \[ \frac {3 a^{2} c x}{2} + \frac {3 a^{2} d x^{2}}{4} + \begin {cases} \frac {\left (\left (32 a^{2} c f^{7} e^{e} + 32 a^{2} d f^{7} x e^{e} + 16 a^{2} d f^{6} e^{e}\right ) e^{- 2 f x} + \left (- 32 a^{2} c f^{7} e^{5 e} - 32 a^{2} d f^{7} x e^{5 e} + 16 a^{2} d f^{6} e^{5 e}\right ) e^{2 f x} + \left (256 i a^{2} c f^{7} e^{2 e} + 256 i a^{2} d f^{7} x e^{2 e} + 256 i a^{2} d f^{6} e^{2 e}\right ) e^{- f x} + \left (256 i a^{2} c f^{7} e^{4 e} + 256 i a^{2} d f^{7} x e^{4 e} - 256 i a^{2} d f^{6} e^{4 e}\right ) e^{f x}\right ) e^{- 3 e}}{256 f^{8}} & \text {for}\: 256 f^{8} e^{3 e} \neq 0 \\\frac {x^{2} \left (- a^{2} d e^{4 e} + 4 i a^{2} d e^{3 e} - 4 i a^{2} d e^{e} - a^{2} d\right ) e^{- 2 e}}{8} + \frac {x \left (- a^{2} c e^{4 e} + 4 i a^{2} c e^{3 e} - 4 i a^{2} c e^{e} - a^{2} c\right ) e^{- 2 e}}{4} & \text {otherwise} \end {cases} \]
Verification of antiderivative is not currently implemented for this CAS.
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